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Partial Derivatives

Given is a function
$\displaystyle u(x,y)$     (1)

in which $x$ and $y$ are independent variables.

The partial derivatives of $u$ with respect to $x$ or $y$, respectively can be obtained by considering $y$ or $x$, respectively as a constant and are written as

$\displaystyle \frac{\partial u}{\partial x} \hspace{1cm}\mbox{and} \hspace{1cm}
\frac{\partial u}{\partial y}.$     (2)


Example 1: $u(x,y)=5x^2+3xy+y^4$.
The partial derivative of $u$ with respect to $x$ can be obtained by considering $y$ as a constant:

$\displaystyle \frac{\partial u}{\partial x}=5\cdot 2\cdot x+3\cdot y+0=10x+3y.$     (3)

The partial derivative of $u$ with respect to $y$ (considering $x$ as a constant) is:
$\displaystyle \displaystyle{\frac{\partial u}{\partial y}=0+3\cdot x+4\cdot y^3=3x+4y^3}.$     (4)

All partial derivatives can be expressed as a vector, which is called the
Gradient of the function $u(x,y)$:

$\displaystyle \mbox{grad }u$ $\textstyle =$ $\displaystyle \nabla u(x,y)=\left(\begin{array}{c}
\frac{\partial u}{\partial x}\\
\frac{\partial u}{\partial y}
\end{array}\right).$ (5)

The gradient represents the direction of highest ascent.

In Example 1, the gradient is:

$\displaystyle \nabla u(x,y)=\nabla (5x^2+3xy+y^4)=\left(\begin{array}{c}
10x+3y\\
3x+4y^3
\end{array}\right).$     (6)



Subsections
next up previous
Next: Higher Partial Derivatives Up: pde Previous: pde
Heiko Enderling 2003-11-13